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adrianawalker16
31.07.2021 •
Chemistry
Calculate the following for test tube 1 and for test tube 2, and record the results in the table:
1-the number of moles of copper(II) sulfate used (Use 159.60 grams/mole as the molar mass of copper(II) sulfate.)
2-the heat absorbed by the water, in joules (Use Q = mCΔT, where 10.0 milliliters of water has a mass of 10.0 grams. Use 4.186 joules/gram degree Celsius as water’s specific heat capacity.)
3-the change in internal energy of the copper(II) sulfate (Assume that the energy released by the copper(II) sulfate is absorbed by the water.)
4-the reaction enthalpy, in joules/mole
Test tube 1 Test tube 2
Moles of copper(II) sulfate
Heat absorbed by water (J)
Change in internal energy (J)
Reaction enthalpy (J/mol)
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