Calculate the kinetic energy of the electrons when radiation of wavelength of 1.50 × 102 nm falls on a metal. the threshold wavelength of the metal is 2.00 4494_files/i011.jpg 102 nm. a. 6.20 ev c. 2.07 ev b. 8.26 ev d. 14.4 ev
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Ответ:
E = hv where h is the Plank's constant and v is the frequency (v = speed of light / wavelength )
E = h (speed of light / wavelength)
E = 6.63x10^-34 ( 3x10^8 )/ (1.50x10^-7 )
E = 1.326x10^-18 J = 8.26 eV
Ответ:
22.99987 or 23 ft
Explanation:
You divide the length value by 30.48
Hope this helps!