Calculate the mass of magnesium carbonate ( MgCO3), in grams, required to produce 110.0 g of carbon dioxide using the following equation: MgCO3 --> MgO CO2
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Ответ:
Explanation:
We have to start with the reaction:
We have the same amount of atoms on both sides, so, we can continue. The next step is to find the number of moles that we have in the 110.0 g of carbon dioxide, to this, we have to know the atomic mass of each atom:
C: 12 g/mol
O: 16 g/mol
Mg: 23.3 g/mol
If we take into account the number of atoms in the formula, we can calculate the molar mass of carbon dioxide:
In other words: . With this in mind, we can calculate the moles:
Now, the molar ratio between carbon dioxide and magnesium carbonate is 1:1, so:
With the molar mass of (. With this in mind, we can calculate the grams of magnesium carbonate:
I hope it helps!
Ответ:
hm
Explanation: