Calculate the mass of sodium hydroxide in 30cm3 of a 0.105 mol/dm3 solution

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Ответ:

swkgp3cevk

24.10.2020

Chemistry

44.04 g/mol

Explanation:

Ideal gas law in terms of density:

$PV=nRT\\\\PV=\frac{w}{M}\times RT\\\\M=\frac{w}{V}\times \frac{RT}{P}\\\\M=\rho\times \frac{RT}{P}$

where,

P = pressure of the gas = 0.789 atm

V = volume of the gas

T = temperature of the gas = 23^0C=(23+273)=296K

n = number of moles of the gas

R = gas constant = 0.0821 Latm/moleK

M = molar mass of gas

w = mass of gas

$\rho$ = density =1.43 g/ml

$M=1.43\times \frac{0.0821\times 296}{0.789}$

M=44.04g/mol

Thus molar mass of the gas is 44.04 g/mol

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