Chemistry: Calculate the molality of a solution formed by dissolving 27.8 g of lii in 500.0 ml of water.

Calculate the molality of a solution formed by dissolving

Ответ:

alexsan5537

12.03.2022

Chemistry

Molarity of a solution : 0.416 M

$Molarity = \frac{(Moles of solute)}{(Volume of solution in L)}$

In our question LiI(Lithium Iodide) is solute and we need to find the moles of LiI.

Given grams of LiI = 27.8g , Volume of solution = 500 mL

$Moles of LiI = \frac{Grams}{Molar mass}$

Molar mass of LiI = 133.85 g/mol

$Moles of LiI = \frac{27.8g}{133.85\frac{g}{mol}}$

Moles of LiI = 0.208 mol

To find molarity we need volume of solution in 'L' , so we need to convert 500 mL to L.

1 L = 1000 mL

$(500 mL)\times \frac{(1L)}{(1000mL)}$

Volume = 0.5 L

$Molarity = \frac{(Moles of solute)}{(Volume of solution in L)}$

$Molarity = \frac{(0.208mol)}{(0.5 L)}$

Molarity = $0.416\frac{mol}{L}$ or 0.416 M

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Ответ:

djkk1367

10.05.2021

Chemistry

Explanation:

particles move rapidly in all directions but collide with each other more frequently than in gases due to shorter distances between particles. With an increase in temperature, the particles move faster as they gain kinetic energy, resulting in increased collision rates and an increased rate of diffusion

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Calculate the molality of a solution formed by dissolving 27.8 g of lii in 500.0 ml of water.

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