Calculate the molarity of 8.42 x 102 mL of solution containing 22.4 g of potassium iodide.

Molarity = 0.154 M

Explanation:

Given data:

Volume of solution = 8.42 × 10² mL ( 8.42 × 10² /1000 = 0.842 L)

Mass of potassium iodide = 22.4 g

Molarity of solution = ?

Solution:

Number of moles of potassium iodide:

Number of moles = mass/molar mass

Number of moles = 22.4 g/ 166.0 g/mol

Number of moles = 0.13 mol

Molarity:

Molarity = number of moles / volume in L

Molarity = 0.13 mol / 0.842 L

Molarity = 0.154 M

0,1,2,3

Explanation: