Calculate the number of moles of NaCl contained in .5000 L of a 1.5 M (Molarity) solution.

The number of moles of NaCl contained in 0.5000 L of a 1.5 M (Molarity) solution is 0.75 moles.

Explanation:

Molar concentration is a measure of the concentration of a solute in a solution, be it some molecular, ionic, or atomic species.

Molarity M is the number of moles of solute that are dissolved in a given volume.

The Molarity of a solution is determined by the following expression:

Molarity is expressed in units .

In this case:

Reemplacing:

Solving:

number of moles of solute= 1.5 M* 0.5 L

number of moles of solute= 0.75

The number of moles of NaCl contained in 0.5000 L of a 1.5 M (Molarity) solution is 0.75 moles.

             6.61 Pounds

Solution:

Step 1: Calculate Mass of Water as;

                        Density  =  Mass  ÷  Volume

Solving for Mass,

                        Mass  =  Density  ×  Volume   (1)

As,

                        Density of Water  =  1 g.cm⁻³

And,

                        3 L of Water  =  3000 cm³

Putting values in equation 1,

                        Mass  =  1 g.cm⁻³  × 3000 cm³

                        Mass  =  3000 g

Step 2: Convert Grams into Pounds;

As,

                        1 Gram  =  0.002204 Pounds

So,

                        3000 Grams  =  X Pounds

Solving for X,

                      X =  (3000 Grams  ×  0.002204 Pounds)  ÷  1 Gram

                      X =  6.61 Pounds