Calculate the poh of a 0.200 m (c2h5)3 aqueous solution given kb= 5.2 x 10^-4
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Ответ:
The dissociation of (C2H5 )3 N takes place as follows:
(C2H5 )3 N --> (C2H5)2N- + C2H5 +
0.2 – x x x
Whereas, dissociation of ethanol is follows:
C2H5 OH --> C2H5 + + OH-
Thus, the concentration of C2H5 + is equivalent to OH-
Kb = [(C2H5)2N- ] [C2H5 + ] / [(C2H5 )3 N ]
5.2 * 10-4 = x^2 / 0.2
x = [OH- ] = 5.01 * 10^-2 M
The concentration of hydroxyl ion is 5.01 * 10^-2 M
P (OH) = - log [OH- ]
= - log [5.01 * 10^-2 ]
= 1.31
The Poh is 1.31
Ответ:
They are closely related the most to Plate Tectonics. They're usually at Convergent plate boundaries.
Explanation:
Hope this helped! Sorry if I'm wrong.
-Bella