Calculate the specific heat capacity of titanium if a 43.56 g sample absorbs 476 J as its temperature changes from 20.13 oC to 41.06 oC. (0.522 J/g oC)

The specific heat capacity of Titanium is found as 0.522 J / g°C.

Explanation:

We have to find the specific capacity using the formula as,

q = m × c × ΔT

Where,

q is the heat absorbed by the sample = 476 J

m is the mass of the sample = 43.56 g

c is the specific heat capacity of the sample = ?

ΔT is the temperature difference  = 41.06° C - 20.13°C = 20.93° C

Now, we have to rewrite the equation to get the specific heat capacity as,

c =

 =

 = 0.522 J / g°C

So the specific heat capacity of Titanium is found as 0.522 J / g°C.

Kerosene is lighter than water and so it floats on the water and continues to burn. Carbon (IV) oxide blankets the flame cutting off the supply of oxygen and extinguishing the fire.

Explanation:

As water is heavier than kerosene, it slips down permitting the kerosene to rise to the surface and continue to burn. Besides, the existing temperature is so high that the water poured on the fire would evaporate before it can extinguish the fire. Thus the kerosene fire cannot be extinguished with water.