Calculate the temperature of the system once equilibrium has been reached. Assume that CP,m for H2O(l) is constant at its values for 298 K (75.3 J⋅mol−1⋅K−1) throughout the temperature range of interest. ΔHfus for ice is 6010 J⋅mol−1.

3 mol

Explanation:

Given data:

Moles of hydrogen = 3 mol

Moles of oxygen = 2 mol

Yield of reaction = 80%

Moles of water produced = ?

Solution:

Chemical equation:

2H₂ + O₂  →  2H₂O

Now we will compare the moles of water with both reactants.

                       H₂           :         H₂O

                        2            :            2

                          3          :             3

                          O₂        :           H₂O

                           1          :              2

                           2          :         2×2 =   4

Hydrogen produced less number of moles of water so it will limiting reactant.

So number of moles of water produced are = 3 mol