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ralewis2931
11.07.2019 •
Chemistry
Calculate the volumetric size of a water molecule in water vapor at normal conditions, assuming 1 mole of the vapor occupies 22.4 l, as if the vapor were an ideal gas. give answer in angstroms, two significant digits. do not write down units in your answer.calculate the volumetric size of a water molecule in water vapor at normal conditions, assuming 1 mole of the vapor occupies 22.4 l, as if the vapor were an ideal gas. give answer in angstroms, two significant digits. do not write down units in your answer.
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Ответ:
Let volumetric size of a water molecule = v
Since, 1 mole of water consists of
molecules of water.
Thus, total volume of 1 mole of water =![volumetric size \times 6.023\times 10^{23}](/tpl/images/0077/5108/83c04.png)
Substitute the value of total volume of 1 mole of water i.e. 22.4 L in above formula.
Convert the unit litre to angstrom
=![3.7\times 10^{-23}\times 10^{27} (A^{o})^{3}](/tpl/images/0077/5108/254ed.png)
=![3.7 \times 10^{4}(A^{o})^{3}](/tpl/images/0077/5108/33c49.png)
Therefore, the volumetric size of the water molecule is![3.7 \times 10^{4}(A^{o})^{3}](/tpl/images/0077/5108/33c49.png)
Ответ:
2.29x10⁻¹² is Ksp of the salt
Explanation:
The Ksp of the metal hydroxide is:
M(OH)₂(s) ⇄ M²⁺ + 2OH⁻
Ksp = [M²⁺] [OH⁻]²
As you can see in the reaction, 2 moles of OH⁻ are produced per mole of M²⁺. It is possible to find [OH⁻] with pH, thus:
pOH = 14- pH
pOH = 14 - 10.22
pOH = 3.78
pOH = -log[OH⁻]
1.66x10⁻⁴ = [OH⁻]
And [M²⁺] is the half of [OH⁻], [M²⁺] = 8.30x10⁻⁵
Replacing in Ksp formula:
Ksp = [8.30x10⁻⁵] [1.66x10⁻⁴]²
Ksp = 2.29x10⁻¹² is Ksp of the salt