Calculate whether a precipitate will form (and why) if 0.35 l of 0.0044 m ca(no3)2 and 0.17 l of 0.00039 m naoh are mixed at 25◦c. ksp for ca(oh)2 is equal to 5.5 × 10−6.

Chemical reaction: Ca(NO₃)₂ + 2NaOH → Ca(OH)₂ + 2NaNO₃.
c₁(Ca(NO₃)₂) · V₁(Ca(NO₃)₂) = c₂(Ca(NO₃)₂) · V₂(Ca(NO₃)₂).
0.0044 M · 0.35 L = c₂(Ca(NO₃)₂) · (0.35 L + 0.17 L).
[Ca²⁺] = c₂(Ca(NO₃)₂) = 0.00296 M.
c₁(NaOH) · V₁(NaOH) = c₂(NaOH) · V₂(NaOH).
0.00039 M · 0.17 L = c₂(NaOH) · (0.35 L + 0.17 L)
[OH⁻] = c₂(NaOH) = 0.0001275 M.
Q(Ca(OH)₂) = [Ca²⁺] · [OH⁻]².
Q = 0.00296 M · (0.0001275 M)² = 4.9·10⁻¹¹.
Ca(OH)₂ does not precipitate because Q < Ksp.

The element that undergoes oxidation release electron and the element that undergo reaction accepts the electron. that’s how electron flow