Can any help me answer this pls

Refer to the attachments

Value of a is -2.

Step-by-step explanation:

Given:

Vertex of the Quadratic function is ( 6 , 2 )

y-intercept of the function is ( 0 , -70 )

The equation of the function in intercept form ,

f(x) = a( x - h )² + k where ( h , k ) is vertex and k is y-intercept.

To find: Value of a.

According to the question, putting values in intercept form we get

-70 = a( 0 - 6 )² + 2

-70 -2 = a(-6)²

36a = -72

a = -2

Therefore, Value of a is -2.