Can somebody help me with this please

In this item, we calculate the moles of nacl with the basis of 1l of solution.
  first, calculate the mass of the solution using the density.
                      m = (1l) x (1000g/1000ml)(1000ml/1l) = 1000g
then, we calculate mass of nacl by multiplying the calculate value with the percentage.
                    m of nacl = (1000 g)(0.0090) = 9 g
then, calculate the moles of nacl by the molar mass.
                    molarity = (9g)(1 mole/ 58.44 g) = 0.1539 mole / l solution or 0.1529m. then, the answer to this item is letter c.