Can someone please explain this to me t,t I could do the second part if i just understood the first-

Theoretical 32.04 g

The precent yeild 87. 39 %

Explanation:

Mole of H2 = m/mw = 4/2 = 2 mol

From the equation

1 mol H2--> 1/2 mol CH3OH

2 mol H2 -->??

So we have 1 mol Ch3oh

Mass of Ch3oh = mole *Mw = 1* 32.04

= 32.04g >>> the theoretically

For percent yeild = actual / theoretical * 100%

( 28.0/32.04) *100% =

87.93%

Its 0.6 pal, had the same question earlier and that's what i found. Hope it helps ;)