How many grams are in 2.30 x 10^23 atoms in Na?

There are 8.786 g

Further explanation

The mole is the number of particles contained in a substance

1 mol = 6.02.10²³

2.30 x 10²³ atoms in Na :

mass :

Answer is: 1 mol CH₄/16 g CH₄.
Chemical reaction: CH₄ + 2O₂ → CO₂ + 2H₂O.
m(CH₄) = 29,5 g.
M(CH₄) = 1·12 g/mol + 4·1 g/mol = 16 g/mol.
n(CH₄) = m(CH₄) ÷ M(CH₄).
n(CH₄) = 29,5 g ÷ 16 g/mol
n(CH₄) = 1,84 mol.
from reaction: n(CH₄) = n(CO₂).
n(CO₂) = 1,84 mol.
m(CO₂) = 1,84 mol · 44 ··/mol.
m(CO₂) = 81 g.
n - amount of substance.