Can you tell me the answers, top from bottom ?

I downloaded the picture and labelled it and attached it here.  Also the answers I have from top to bottom are:
- Beaker
- Mixture (Suspension; filtration is only usually an effective method of
                 separation if the mixture is a liquid-solid suspension)
-Filter Funnel
-Filter Paper
-Residue
-Conical Flask
-Filtrate 

If you need annotations let me know

3853 g

Step-by-step explanation:

M_r: 107.87

         16Ag + S₈ ⟶ 8Ag₂S; ΔH°f =  -31.8 kJ·mol⁻¹

1. Calculate the moles of Ag₂S

Moles of Ag₂S = 567.9 kJ × 1 mol Ag₂S/31.8kJ = 17.858 mol Ag₂S

2. Calculate the moles of Ag

Moles of Ag = 17.86 mol Ag₂S × (16 mol Ag/8 mol Ag₂S) = 35.717 mol Ag

3. Calculate the mass of Ag

Mass of g = 35.717 mol Ag × (107.87 g Ag/1 mol Ag) = 3853 g Ag

You must react 3853 g of Ag to produce 567.9 kJ of heat