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IsabelAyshi
23.03.2020 •
Chemistry
Carbon is allowed to diffuse through a steel plate 13-mm thick. The concentrations of carbon at the two faces are 0.654 and 0.377 kg C/m3 Fe, which are maintained constant. If the preexponential and activation energy are 6.5 × 10-7 m2/s and 82 kJ/mol, respectively, calculate the temperature (in K) at which the diffusion flux is 3.2 × 10-9 kg/(m2-s).
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Ответ:
T = 1177.95 K
Explanation:
Equation for diffusion flux is given as;
J = D(ΔC/Δx)e^(Qd/RT)
Where J = 3.2 × 10^(-9) kg/m².s
Qd = 82Kj/mol = 82,000 J/mol
D = 6.5 × 10^(-7) m²/s
ΔC = 0.654 - 0.377 = 0.277 kg.C/m³
Δx = 13mm = 0.013m
R = 8.314 J/mol.k
Let's make T the subject of the equation;
T = Qd/(R In D(ΔC/JΔx))
T = 82,000/(8.314 In 6.5 × 10^(-7)(0.277/(3.2 × 10^(-9) x 0.013))
T = 82000/(8.314In 4328.125) = 1177.95 K
Ответ:
Sample Response: The equation of Relationship 1 is y = 3/2x + 5. Substitute 50 for y and solve to find that x = 30. Multiply 30 by 5/6, the rate of change of Relationship 2, to get 25. This means that the initial value would need to be 25 to get to 50 when the input is 30.