Chromium(iii) sulfate is a transition metal compound containing the metal chromium and the polyatomic ion sulfate.
the oxidation state of chromium in this compound is
, and the chemical formula of the compound is
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Ответ:
The oxidation state is +3.
chemical formula of compound is Cr₂(SO₄)₃.
Explanation:
Calculation of oxidation state:
Cr₂(SO₄)₃
Cr= ?
The oxidation state of SO₄ = -2
2x + 3( -2) = 0
2x - 6 = 0
2x = 6
x = 6/2
x= 3
The oxidation state of Cr is +3.
The Cr has valency of 3 so three SO₄ will require while the valency of SO₄ is 2 so two Cr will require.
Cr×2 and SO₄×3
Cr₂(SO₄)₃
we know that oxidation state of Cr is +3 so (3×2) = 6
and the oxidation state of SO₄ is -2 so (-2× 3) = -6
6-6= 0
The overall charge is 0, the compound will be neutral.
Ответ:
a) oxidation number of chromium is +3
b) formula of the compound is Cr2(SO4)3
Explanation:
From the name of the compound, we can see that the oxidation state of chromium is +3
We know the sulphate ion to to be SO4^2-
According to the rules of writing the formula of compounds from valencies, the valency of chromium is 3 while that is the sulphate ion is 2.
The both species can now exchange valency
Cr2(SO4)3 This is the correct formula of the compound
Ответ:
Answer
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