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sbelgirl2000
27.06.2019 •
Chemistry
Click the button within the activity, and analyze the relationship between the two reactions that are displayed. the reaction that was on the screen when you started and its derivative demonstrate that the change in enthalpy for a reaction, î”h, is an extensive property. using this property, calculate the change in enthalpy for reaction 2. reaction 1: c3h8(g)+5o2(g)→3co2(g)+4h2o(g), î”h1=â’2043 kj reaction 2: 6c3h8(g)+30o2(g)→18co2(g)+24h2o(g), î”h2=?
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Ответ:
-12 258 kJ
Step-by-step explanation:
Reaction 1: C₃H₈(g)+5O2(g) ⟶ 3CO₂(g)+ 4H₂O(g); ΔH₁ = - 2 043 kJ
Reaction 2: 6C₃H₈(g)+30O2(g) ⟶ 18CO₂(g)+ 24H₂O(g); ΔH₂ = -12 258 kJ
Reaction 2 is Reaction 1 multiplied by 6.
ΔH is an extensive property, so you must also multiply ΔH by 6.
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