weridness80
24.08.2019 •
Chemistry
Consider separate 1.0-l samples of he(g) and uf6(g), both at 1.00 atm and containing the same number of moles. what ratio of temperatures for the two samples would produce the same root mean square velocity? consider separate 1.0-l samples of he(g) and uf6(g), both at 1.00 atm and containing the same number of moles. what ratio of temperatures for the two samples would produce the same root mean square velocity?
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Ответ:
V = RMS velocity
R = 8.3145 J/K*mole
T = Temperature K
MW = Molecular weigh in Kg
Ответ:
MgSO4.7H2O
Explanation:
The heating removes all the water (H2O) in the crystal.
The mass of the water removed = 82-40.1 = 41.9 grams.
The formula of the hydrated salt = MgSO4. xH2O
The ratio in of the masses of MgSO4 : H2O = 40.1 : 41.9
Dividing these by the molar masses we get
40.1/ 120.4 to 41.9 / 18.016
= 0.33 : 2.33
= 1 : 7.
So there are 7 water molecules n the hydrate.