Consider the equations below.
CH,(9) →C(s)+2H2 (9) AH, = 74.6 kJ
C(s) + 2Cl2(g) → CCI (9) AH2 = -95.7 kJ
2H2(g) + 2Cl2(g) → 4HCI(9) AH2 = -184.6 kJ
CH, (g) + 4C12(g) → CCI,(9) + 4HCl(g) AH, = -205.7 kJ
Complete the following based on the diagram.
Arrow A:
Arrow B:
Arrow C:
Arrow D:
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