Consider the following acid and bases HCO2H ka = 1.8 x 10^-4 HOBr Ka = 2.0 x 10^-9
(C2H5)2NH kb = 1.3 x 10-3
HONH2 kb = 1.1 x 10^-8
choose sobstances to create ph = 4 buffer solutions:
select all tha apply
HONH3NO3
HOBr
NaOBr
(C2H5)2NH2Cl
(C2H5)2NH
HCO2H
KHCO2
HONH2

Density is the ratio of mass to volume. The metal is copper

We have the following information;

Mass of the beads = 425 grams

Volume of water displaced = 48.0 cm3

Since volume of water displaced = volume of the object

volume of the object = 48.0 cm3

Density = 425 grams/48.0 cm3

Density = 8.86 g/mL

Hence, the metal is copper

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