Consider the reaction between aluminum and oxygen in a closed container. the equation for this reaction is:
4al + 3o2 -> 2al2o3
what is true about this chemical equation?

a. on the product side of the equation above, there are 2 atoms of aluminum and 3 atoms of oxygen.

b. the 3 in front of o2 represents 3 atoms of oxygen.

c. the number of atoms, molecules, and ions of reactants is equal to the number of atoms, molecules, and ions of the products.

d. for every 4 atoms of aluminum and 3 molecules of oxygen gas, 2 units of the compound of aluminum and oxygen are produced.

D. For every 4 atoms of aluminum and 3 molecules of oxygen gas, 2 units of the compound of aluminum and oxygen are produced.

→ This is true. For every 4 atoms of aluminium and 3 molecules of oxygen 2 units of aluminiumoxide will be produced.

Explanation:

Step 1: The balanced equation

4Al + 3O2 → 2Al2O3

A. On the product side of the equation above, there are 2 atoms of aluminum and 3 atoms of oxygen.

→ This is false. On the product side (2Al2O3) we have 4 atoms of Al and 6 atoms of oxygen

B. The 3 in front of O2 represents 3 atoms of oxygen.

→ This is false. The 3 means 3 oxygen (O2) molecules. Each molecule contains 2 oxygen (O) atoms.

C. The number of atoms, molecules, and ions of reactants is equal to the number of atoms, molecules, and ions of the products.

  → This is false. the number of atoms in the reactants is the same as the number of atoms in the product. ... However, the number of molecules in the reactants and products are not the same. The number of molecules is not conserved during the reaction

D. For every 4 atoms of aluminum and 3 molecules of oxygen gas, 2 units of the compound of aluminum and oxygen are produced.

→ This is true. For every 4 atoms of aluminium and 3 molecules of oxygen 2 units of aluminiumoxide will be produced.