Consider the reaction nobr(g) => no(g) + 1/2 br2(g). a plot of 1/[nobr] vs time give a straight line with a slope of 2.00 m-1s-1. the order of the reaction and the rate constant, respectively, are

Thus, the order of the reaction is 2.

The rate constant of the graph which is :- 2.00 M⁻¹s⁻¹

Explanation:

The kinetics of a reaction can be known graphically by plotting the concentration vs time experimental data on a sheet of graph.

The concentration vs time graph of zero order reactions is linear with negative slope.

The concentration vs time graph for a first order reactions is a exponential curve.  For first order kinetics the graph between the natural logarithm of the concentration vs time comes out to be a straight graph with negative slope.

The concentration vs time graph for a second order reaction is a hyberbolic curve. Also, for second order kinetics the graph between the reciprocal of the concentration vs time comes out to be a straight graph with positive slope.

Considering the question,

A plot of 1/[NOBr] vs time give a straight line with a slope of 2.00 M⁻¹s⁻¹.

Thus, the order of the reaction is 2.

Also, slope is the rate constant of the graph which is :- 2.00 M⁻¹s⁻¹

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