Consider the reaction of a to form b.2a(g) ↔ b(g) kc = 1.8 × 10-3 (at 298 k) a reaction mixture at 298 k initially contains [a] = 0.50m. what is the concentration of b when the reaction reaches equilibrium?

ANSWER:  

The 75% of 400 is 300.

SOLUTION:

Given, 75% of 400.  

We have to Write and evaluate an expression to find the answer. Then we have explain how to use the model to justify the answer.

Now, let x and y be any two numbers such that, 0 ≤ y ≤ 100

Now, let us substitute the given values in above expression.

We have to do the same procedure for any given values.

Hence, the 75% of 400 is 300.