alexabessin

27.02.2020 • 

Chemistry

Consider the reaction of ethyl acetate with sodium hydroxide: CH3COOC2H5(aq)+NaOH(aq)⇌CH3COONa(aq)+C2H5OH(aq) The reaction is first order in NaOH and second order overall. What is the rate law? View Available Hint(s) Consider the reaction of ethyl acetate with sodium hydroxide: The reaction is first order in and second order overall. What is the rate law? rate=k[CH3COOC2H5]2[NaOH]2 rate=k[CH3COOC2H5][NaOH]2 rate=k[NaOH] rate=k[CH3COOC2H5] rate=k[CH3COOC2H5][NaOH] rate=k[CH3COOC2H5]2[NaOH]

Ответ:

srshelton

19.01.2022

Chemistry

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The rate law is

Explanation:

Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

For the given reaction:

k= rate constant

Rate law:

For the given rate law:

y =1 =  order with respect to

n = total order = 2

2= (x+y)

2= (x+1)

x= 1

Thus order with respect to is 1 and rate law is :

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Ответ:

bevanscory123

21.04.2022

Chemistry

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The problem here is that according to aufbau principle before 3d orbital 4s subshell comes.after filling 3p orbital with electrons you have 4 electrons left, you place two in 4s with opposite spin and the other two in 3d in any of its two orbitals of total five orbitals with the same spin.

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