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davelopez979
30.01.2020 •
Chemistry
Decomposition of potassium chlorate (kclo3) produces potassium chloride (kcl) and pure oxygen (o2). the balanced equation for the reaction is as follows.
mc017-1.jpg
what volume of oxygen gas is released at stp if 10.0 g of potassium chlorate is decomposed? (the molar mass of kclo3 is 122.55 g/mol.)
0.914 l
1.83 l
2.74 l
3.66 l
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Ответ:
1. The balanced reaction would be:
2KClO3 --> 2KCl + 3O2
We are given the amount of potassium chlorate for the reaction. This will be the starting point of our calculation.
10.0 g KClO3 ( 1 mol KClO3 / 122.55 g KClO3) (3 mol O2 / 2 mol KClO3) = 0.1224 mol O2
V = nRT/P =0.1224 mol O2 x 273 K x 0.08206 atm L/mol K / 1 atm
V=2.74 L
Ответ:
Be has a charge of 2+, and O has a charge of 2-. The coefficients cancel out leaving BeO
2) SO2+ H2O--> H2SO3