![cayleemiller02](/avatars/32427.jpg)
cayleemiller02
24.02.2021 •
Chemistry
Determine the block of the element Iron which has 26 atomic number:
Solved
Show answers
More tips
- W Work and Career How to behave at an interview? Tips from an HR specialist...
- F Family and Home How to Keep Your Home Warm: Tips and Tricks...
- D Dating, Love, Relationships Does a Person s Character Depend on the Color of Their Eyes?...
- O Other Childhood Fears: What Many of Us Experienced...
- H Health and Medicine Simple and Effective: How to Get Rid of Cracked Heels...
- O Other How to Choose the Best Answer to Your Question on The Grand Question ?...
- L Leisure and Entertainment History of International Women s Day: When Did the Celebration of March 8th Begin?...
- S Style and Beauty Intimate Haircut: The Reasons, Popularity, and Risks...
- A Art and Culture When Will Eurovision 2011 Take Place?...
- S Style and Beauty How to Choose the Perfect Hair Straightener?...
Answers on questions: Chemistry
- P Physics Whatare two diffent units that represent work...
- M Mathematics It was estimated that 12,000 people attended the football game friday night. what could have been their actual number of people at the game...
- B Business The Grass is Greener Company borrows money from a bank. Part of the loan agreement requires Grass is Greener to maintain stockholders equity at least 40% of assets or...
- C Chemistry Question 3 1 pts What is the molar mass of C13H21N03 (albuterol), a drug used to treat asthma? Reminder: molar mass is always 4 numbers g/mol...
Ответ:
ok
Explanation:
Ответ:
Iron
Explanation:
Ответ:
450 mL
Explanation:
First we calculate how many NaCl moles would there be in 1.5 L of a 0.75 M solution, using the definition of molarity:
Molarity = moles / LitersMoles = Molarity * LitersMoles = 1.5 L * 0.75 M =1.125 molOnce again using the definition of molarity, we now calculate how many liters of a 2.5 M solution would have 1.125 moles:
Liters = 1.125 mol / 2.5 M = 0.45 LFinally we convert 0.45 liters to mL:
0.45 L * 1000 = 450 mL