Determine the change in energy when an electron transitions from n= to n=5?
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Ответ:
ΔE = 13.056 ev
Explanation:
Energy associated with nth state is,
En = -13.6/n²
For n = 1
E₁ = -13.6 / 1²
E₁ = -13.6/1
E₁ = -13.6 ev
Kinetic energy of electron = -E₁ = 13.6 ev
For n = 5
E₅ = -13.6 / 5²
E₅ = -13.6/25
E₅ = -0.544 ev
Kinetic energy of electron = -E₅ = 0.544 ev
Wavelength of radiation emitted:
ΔE = hc/λ = E₅ - E₁
by putting values,
ΔE = -0.544ev - (-13.6 ev )
ΔE = 13.056 ev
Ответ:
B Is Your Answer
Explanation: