Chemistry: Determine the electron geometry (eg) and molecular geometry (mg) of [tex]ch_3^+[/tex]. a) eg = bent, mg = bent b) eg = tetrahedral, mg = trigonal planar c) eg = trigonal pyramidal, mg = trigonal pyramidal d) eg = tetrahedral, mg = tetrahedral e) eg = trigonal planar, mg = trigonal planar

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Determine the electron geometry (eg) and molecular

lennyatme

13.01.2022

Answer : The correct option is, (e) eg = trigonal planar, mg = trigonal planar

Explanation :

Formula used :

$\text{Number of electron pair}=\frac{1}{2}[V+N-C+A]$

where,

V = number of valence electrons present in central atom

N = number of monovalent atoms bonded to central atom

C = charge of cation

A = charge of anion

The given molecule is, CH_3^+

$\text{Number of electron pair}=\frac{1}{2}\times [4+3-1]=3$

That means,

Bond pair = 3

Lone pair = 0

The number of electron pair are 3 that means the hybridization will be sp^2 and the electronic geometry of the molecule will be trigonal planar.

Hence, the electron geometry (eg) and molecular geometry (mg) of CH_3^+ is, trigonal planar and trigonal planar respectively.

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