Determine the mass in grams of 4.69 x 1021 atoms

Ответ:

elirosejohlandancel

11.05.2021

1.07 g Ba

Explanation:

Hello there!

In this case, according to the definition of the Avogadro's number and the molar mass, it is possible to say that 6.022x10^{23} atoms of barium equal one mole, and at the same time, 1 mole equals 137.327 grams of this element; thus, it is possible to say that 6.022x10^{23} atoms of barium have a mass of 137.327 grams; therefore, it i possible for us to calculate the required mass in grams as shown below:

$4.69x10^{21}atoms*\frac{137.327gBa}{6.022x10^{23} atoms} \\\\=1.07gBa$

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Ответ:

whiterm04

03.05.2022

Chemistry

Hello! data: p (pressure) = 1.25 atmv (volume) = ? (in l)t (temperature) = 298 kn (number of mols) = 0.900 molesr (gas constant) = 0.082 (atm*l/mol*k)apply the data to the clapeyron equation (ideal gas equation), see: $p*v = n*r*t$ $1.25*v = 0.900*0.082*298$ $1.25v = 21.9924$ $v = \dfrac{21.9924}{1.25}$ $v = 17.59392\: \to\: \boxed{\boxed{v\approx 17.6\: l}}\end{array}}\qquad\checkmark$ i hope this . =)

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Determine the mass in grams of 4.69 x 1021 atoms of barium. (The mass of one mole of barium is 137.33 g.)

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