Determine the mass of solute required to form 275ml of a 0.42m kclo3 solution
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Ответ:
.42M=x moles/.275litres
xmoles=.42M*.275litres= .1155 moles
molar mass of KClO3 = 122.548 grams/moles
mass= 122.548grams/moles* .1155moles= 14.15 grams of PotassiumClorate.\Hopes this loves or thanks.
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