Chemistry: Determine the value of kc for the following reaction if the equilibrium concentrations are as follows: [hcl]eq = 0.13 m, [hi]eq = 5.6 × 10-16 m, [cl2]eq = 0.0019 m. 2 hi(g) + cl2(g) ⇌ 2 hcl(g) + i2(s)

Determine the value of kc for the following reaction

Ответ:

bandnerd1

11.03.2022

The value of K_c is $2.836\times 10^{31}$

Explanation:

Concentration equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric coefficients. It is represented by $K_{c}$

For a general chemical reaction:

$aA+bB\rightarrow cC+dD$

The expression for $K_{c}$ is written as:

$K_{c}=\frac{[C]^c[D]^d}{[A]^a[B]^b}$

For the given chemical reaction:

$2HI(g)+Cl_2(g)\rightleftharpoons 2HCl(g)+I_2(s)$

The expression for K_c is written as:

$K_c=\frac{[I_2][HCl]^2}{[HI]^2[Cl_2]}$

The concentration for solid substances are taken to be 1.

We are given:

$[HI]_{eq}=5.6\times 10^{-16}M$

$[HCl]_{eq}=0.13M$

$[Cl_2]_{eq}=0.0019M$

Putting values in above equation, we get:

$K_c=\frac{(0.13)^2}{(5.6\times 10^{-16})^2\times (0.0019)}\\\\K_c=2.836\times 10^{31}$

Hence, the value of K_c is $2.836\times 10^{31}$

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Ответ:

cecilysimpson7521

15.12.2022

Chemistry

45 grams

Step-by-step explanation:

1st order: 27 people

15 people:

100 g

Ginger: 20 g

Turmeric: 25 g

Coriander: 35 g

Cumin Seeds: 20 g

20+25+35+20=60+40=100

For 1 person:

Ginger: 1 1/3 g

Turmeric: 1 2/3 g

Coriander: 2 1/3 g

Cumin Seeds: 1 1/3 g

Multiply all that by 27

For 27 people:

Ginger: 36 g

Turmeric: 45 g

Coriander: 63 g

Cumin Seeds: 36 g

45 g for Turmeric

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Determine the value of kc for the following reaction if the equilibrium concentrations are as follows: [hcl]eq = 0.13 m, [hi]eq = 5.6 × 10-16 m, [cl2]eq = 0.0019 m. 2 hi(g) + cl2(g) ⇌ 2 hcl(g) + i2(s)

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