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WildfireintheHeart
24.09.2019 •
Chemistry
Douglasite is a mineral with the formula 2kcl • fecl2 • 2h2o. calculate the mass percent of douglasite in a 455.0-mg sample if it took 37.20 ml of a 0.1000 m agno3 solution to precipitate all the cl2 as agcl. assume the douglasite is the only source of chloride ion.
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Ответ:
The mass percentage is 63.3%
Explanation:
First we need to know how much of the AgNO3 we are using to precipitate the chloride, for this we use:
(37.2 ml * 0.1 M)/1000 ml = 0.00372 moles of AgNO3 which means 0.00372 moles of silver.
the relation between Ag and Cl in the precipitation is 1:1, so we can determine that in our sample we have 0.00372 moles of Cl- and in grams we have 131 mg.
Now we need to know how much of the Douglasite is actually chloride. For that we calculate the molar mass:
Mr = 2*39 + 4*35.45 + 55.85 + 2*18 = 311.65 g/mole
Of that 311.65 grams, 141.8 are Cl. So we could calculate how much of the sample is actual Douglasite:
141.8 g Cl --> 311.65 g Douglasite
0.131 g Cl --> x = 0.288 g douglasite.
The sample is 0.455 and represents 100 %
Then, the 288 mg of douglasite is the 63.3 %
Ответ:
2880x^2y
Step-by-step explanation:
hope this helps