En una muestra de jugo de limón la concentración de H1 es de 3.8x10 a la 4 potencia ¿ cual es su PH considerando que 378= 0.58
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Ответ:
pH = 3.42
Explanation:
Para calcular el pH necesitamos usar la siguiente expresión:
pH = -log[H⁺]
Por tanto, solo necesitamos reemplazar el valor dado de [H⁺] en la expresión anterior y se determina su pH:
pH = -log(3.8x10⁻⁴)
pH = 3.42Por tanto el pH de la muestra de jugo de limón es 3.42
Ответ:
Step-by-step explanation: