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jngonzo1226
06.06.2020 •
Chemistry
Estimate the freezing point depression of 0.19
m C12H22O11(aq). The freezing point constant of water is 1.86 K · kg/mol.
Answer in units of ◦C.
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Ответ:
0.3634 °C
Explanation:
In this question, we are tasked with calculating the freezing point depression of 0.19 M C12H12O11( sucrose)
Mathematically this can be calculated using the formula;
ΔTf = i * kf * m
where ΔTf is the freezing point depression
i is Van’t Hoff factor
kf is the molal freezing point depression for the solvent
m is the molality of the solution
From the question we identify the following;
Since sucrose is a non-electrolyte, i = 1 ( i refers to the number of moles of particles obtained when 1 mol of solute dissolves)
m is 0.19
kf = 1.86
substituting these values into the equation, we have
ΔTf = 1 * 1.86 * 0.19 = 0.3534 °C
Ответ:
I believe "frisking" is your answer, hope it helps : )