lillygon81
24.12.2019 •
Chemistry
Ethanol (ch3ch2oh) has been suggested as an alternative fuel source. ethanol’s enthalpy of combustion is hcomb = –1368 kj/mol. what volume of ethanol (d = 0.789 g/ml) is required to produce the same amount of energy as 1 gallon of gasoline, which can be modeled as isooctane (c8h18) with an energy density of 32.9 kj/ml? (1 gal = 3.785 l; d = 0.703 g/ml)
a. 1.41 gal
b. 0.85 gal
c. 1.00 gal
d. 1.15 gal
d. 0.90 ga
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Ответ:
a) V = 1.41 gal
Explanation:
Ethanol:
∴ Hcomb = - 1368 KJ/mol( - ) exothermic reaction
∴ δ = 0.789 g/mL
∴ Mw Ethanol = 46.07 g/mol
⇒ Eδ = (1368 KJ/mol)(mol/46.07 g)(0.789 g/mL) = 23.4285 KJ/mL
isooctane:
∴ Eδ = 32.9 KJ/mL
∴ δ = 0.703 g/mL
1 gal = 3785 mL⇒ E = (32.9 KJ/mL)(3785 mL) = 124526.5 KJ
Volume of Ethanol:
⇒ (Eδ)(V) = 124526.5 KJ
⇒ V = (124526.5 KJ)/(23.4285 KJ/mL) = 5315.167 mL
⇒ V = (5315.167 mL)( gal/3785 mL) = 1.404 gal ≅ 1.41 gal
Ответ:
U already got an answer from the other side