exactly 1mol of n2o4 is placed in an empty 1 l container. if at equilibrium n2o4 is dissociated 20%, what is the value of equilibruim constant

K = 0.2

Explanation:

Based on the chemical dissociation of N₂O₄:

N₂O₄ ⇄ 2NO₂

The equilibrium constant, K, of the reaction is:

K = [NO₂]² / [N₂O₄]

Now, if 20% of N₂O₄ is dissociated, 80% remains as N₂O₄ = 0.8mol/L = 0.8M

as 20% is dissociated, 0.2moles of N₂O₄ were dissociated and 0.2*2 = 0.4mol/L of NO₂ are produced.

Replacing in K:

K = [0.4M]² / [0.8M]

Explanation:

A chemical change in a changes that leads to formation new product or chemical substance having new qualities both physical and chemical.

Therefore, chemical changes can be

1. Gas Production

2. Substances Dissolve to form new substance or solution.

3. Heat is Released is a chemical change.

4. Bubbling occurs.

Rest all are examples of physical changes.