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bryanmcmillianjr
10.10.2019 •
Chemistry
Examine the statement and balanced equation.
pure elemental iron undergoes a single replacement reaction with sulfuric acid (h2so4) to produce iron(iii) sulfate (fe2(so4)3) and hydrogen gas.
2fe + 3h2so4 → fe2(so4)3 + 3h2
(m fe = 55.8 g/mol, m h2so4 = 98.1 g/mol, m fe2(so4)3 = 399.9 g/mol, m h2 = 2.0 g/mol)
if 3.21 x 1012 mol of iron(iii) sulfate are formed, how many g of it will be produced?
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Ответ:
The answer to your question is: 1.28 x 10 ¹⁵ g of Fe₂(SO₄)₃
Explanation:
Single replacement reaction:
2Fe + 3H₂SO₄ → Fe₂(SO₄)₃ + 3H₂
M Fe = 55.8 g/mol
M H₂SO₄ = 98.1 g/mol
M Fe₂(SO₄)₃ = 399.9 g/mol
M H₂ = 2.0 g/mol
Fe₂(SO₄)₃ = 3.21 x 10¹² mol
Fe₂(SO₄)₃ = ? g
1 mol of Fe₂(SO₄)₃ 399.9 g/mol of Fe₂(SO₄)₃
3.21 x 10¹² mol Fe₂(SO₄)₃ x
x = (3.21 x 10¹² x 399.9 ) / 1
x = 1.28 x 10 ¹⁵ g of Fe₂(SO₄)₃
Ответ:
i didn't put an answer because it would take me a while, but i have a link that could help
Explanation:
https://mars.nasa.gov/msl/mission/communications/