Chemistry: Ferrophosphorus (fe2p) reacts with pyrite (fes2) producing iron(ii) sulfide and a compound that is 27.87% p and 72.13% s by mass and has a molar mass of 444.56 g/mol. a. determine the empirical and molecular formulas of this compound. b. empirical formula: molecular formula: c. write a balanced chemical equation for this reaction. do not include phases.

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Ferrophosphorus (fe2p) reacts with pyrite (fes2)

Anderson0300

15.01.2022

The molecular formula of the compound = $P_4S_{10}$

The empirical formula of the compound = $P_2S_{5}$

The balanced chemical equation for this reaction:

$4Fe_2P+18FeS_2\rightarrow 26FeS+P_4S_{10}$

Explanation:

Compound that is 27.87% P and 72.13% S by mass and has a molar mass of 444.56 g/mol.

Molar mass of compound = 444.56 g/mol

Number of phosphorus atom = x

Number of sulfur atom = y

Atomic mass of phosphorus 31 g/mol

Atomic mass of sulfur = 32 g/mol

Percentage of element in compound :

$=\frac{\text{number of atoms}\times text{Atomic mass}}{\text{molar mas of compound}}\times 100$

Phosphorus :

$27.87\%=\frac{x\times 31 g/mol}{444.56 g/mol}\times 100$

x = 4

Sulfur :

$72.13\%=\frac{y\times 32 g/mol}{444.56 g/mol}\times 100$

y = 10

The molecular formula of the compound = $P_4S_{10}$

Empirical formula is the simplest chemical formula which depicts the whole number of atoms of each element present in the compound.

The empirical formula of the compound = $P_2S_{5}$

The balanced chemical equation for this reaction:

$4Fe_2P+18FeS_2\rightarrow 26FeS+P_4S_{10}$

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