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24.11.2020 •
Chemistry
Find the mass of AlCl3 that is produced when 3.58 moles of Al2O3 react with excess HCl according to the following equation.
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Ответ:
Al2O3(s) + 6HCl(aq) → 2AlCl3(aq) + 3H2O(l)
Moles of Al2O3, m = 3.58 moles.
We need to find the mass of AlCl3 produced.
Solution :
1 mole of Al2O3 produce 2 moles of AlCl3.
So, 3.58 moles of AlCl3 produce 7.16 moles of AlCl3.
Mass of AlCl3 produced is :
m = moles × molecular mass of AlCl3
m = 7.16 × 133.34 g
m = 954.714 g
Therefore, mass of AlCl3 produced is 954.714 g.
Hence, this is the required solution.
Ответ:
The egg is changed from liquid to solid
Explanation:
The law of conservation of mass states that "Matter/mass can neither be created nor destroyed but can be converted from one form to another".
Inside of the Egg is liquid in nature and during the process of cooking the egg the liquid changes to solid.
THAT IS HOW MATTER IS CONSERVED WHILE COOKING AN EGG