Find the percent composition of chromium(|||) fluoride (CrF3), which is commonly used as a dye in textiles

%Cr = 47.71%

%F = 52.29%

Explanation:

To do this, we need the atomic weights of all the elements in the chromiun fluoride, which are the following:

Cr: 51.996 g/mol

F: 18.998 g/mol

With these atomic weights, let's calculate the molecular mass of the chromium fluoride:

MM CrF₃ = (51.996) + (18.998 * 3) = 108.99 g/mol

Now, to get the percent composition, all we have to do is divide the atomic weight of each element by the molecular mass, and then, multiply by 100%:

% = (AW / MM) * 100

Replacing with each element:

%Cr = (51.996 / 108.99) * 100

%F = 100 - 47.71

Hope this helps

(+2)

Explanation:The formula of the mohr salt is, Mohr salt is also known as ammonium ferrous sulfate or ammonium iron(II)sulfate. It is the inorganic compound which containing two different cations which are and . It is classified as a double salt of ferrous sulfate and ammonium sulfate.