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isaiah1027
21.02.2020 •
Chemistry
For the following reaction, Kc = 255 at 1000 K. CO(g)+Cl2(g)⇌COCl2(g) A reaction mixture initially contains a CO concentration of 0.1550 M and a Cl2 concentration of 0.172 M at 1000 K.
What is the equilibrium concentration of CO at 1000 K?
What is the equilibrium concentration of Cl2 at 1000 K?
What is the equilibrium concentration of COCl2 at 1000 K?
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Ответ:
Given reaction is:
0.1550 0.172 O
initial
0.1550-x 0.172-x x
Equilibrium
Now,
→![K_c = \frac{[COCl_2]}{[CO][Cl_2]}](/tpl/images/0519/6554/f9140.png)
By substituting the values, we get
or,
(a)
Equilibrium constant of [CO],
=![0.1550-x](/tpl/images/0519/6554/5287c.png)
=![0.016 \ M](/tpl/images/0519/6554/e5736.png)
(b)
Equilibrium constant of [Cl₂],
=![0.172-x](/tpl/images/0519/6554/5a2d7.png)
=![0.033 \ M](/tpl/images/0519/6554/fbac3.png)
(c)
Equilibrium constant of [COCl₂],
=![x](/tpl/images/0519/6554/a0e3f.png)
=![0.139 \ M](/tpl/images/0519/6554/425c0.png)
Thus the above responses are correct.
Learn more about equilibrium here:
link
Ответ:
The equilibrium concentration of CO at 1000 K is 0.016 M , the equilibrium concentration of
at 1000 K is= 0.033 M and the equilibrium concentration of
at 1000 K is 0.139 M
Explanation:
Initial concentration of
Initial concentration of
The given balanced equilibrium reaction is,
Initial conc. 0.1550 M 0.172 M 0 M
At eqm. conc. (0.1550-x) M (0.172-x) M (x) M
The expression for equilibrium constant for this reaction will be,
we are given :![K_c=255](/tpl/images/0519/6554/dbed6.png)
Now put all the given values in this expression, we get :
Thus the equilibrium concentration of CO at 1000 K is= (0.1550-x) M =(0.1550-0.139) M = 0.016 M
Thus the equilibrium concentration of
at 1000 K is= (0.172-x) M =(0.172-0.139) M = 0.033 M
Thus the equilibrium concentration of
at 1000 K is= x M = 0.139 M
Ответ:
B
Explanation: