For which of the following equilibria does `"k"_("eq") = ["o"_2]`? a. o2(l) o2(g) b. 2o3(g) 3o2(g) c. 2h2o(l) 2h2(g) + o2(g) d. 2hg(s) +o2(g) 2hgo(s)

For plato users

the answer is a. O2(l) O2(g)

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For a hypothetical reaction:

aA ↔ bB

the equilibrium constant is given as:

Keq = [B]^b/[A]^a

activity of pure solids and liquids = 1

For the given reactions:

A) O2(l) ↔ O2(g)

Keq = [O₂]

B) 2O3(g) ↔ 3O2(g)

Keq = [O₂]³/[O₃]²

C) 2H2O(l) ↔2H2(g) + O2(g)

Keq = [H₂]²[O₂]

D) 2Hg(s) + O2(g) ↔ 2HgO(s)

Keq = [Hg]²[O₂]

Ans: A

Explanation:

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