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Ответ:

Aaron5795

24.03.2023

Chemistry

pH of the solution is 3.70

Explanation:

The given weak acid (HA) and it's sodium salt (NaA) forms a buffer system. According to Henderson-Hasselbalch equation for this buffer system-

$pH=pK_{a}+log(\frac{n_{A^{-}}}{n_{HA}})$

Where, $n_{A^{-}}$ and $n_{HA}$ represent number of moles of $A^{-}$ ion and HA respectively.

Here $\frac{n_{A^{-}}}{n_{HA}}=2$ and $pK_{a}=-logK_{a}=-log(4.0\times 10^{-4})=3.40$

So, pH=3.40+log2=3.70

Hence pH of the solution is 3.70

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