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khoadominh2206
28.01.2020 •
Chemistry
Given 4.80g of ammonium carbonate, find:
number of moles of the compound
number of moles of ammonium ions
number of moles of carbonate ions
number of moles of hydrogen atoms
number of hydrogen atoms
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Ответ:
1) 0.05 mol.
2) 0.1 mol.
3) 0.05 mol.
4) 0.4 mol.
5) 2.4 x 10²³ molecules.
Explanation:
1) Number of moles of the compound:
no. of moles of ammonium carbonate = mass/molar mass = (4.80 g)/(96.09 g/mol) = 0.05 mol.
2) Number of moles of ammonium ions :
Ammonium carbonate is dissociated according to the balanced equation:(NH₄)₂CO₃ → 2NH₄⁺ + CO₃²⁻.
It is clear that every 1.0 mole of (NH₄)₂CO₃ is dissociated to produce 2.0 moles of NH₄⁺ ions and 1.0 mole of CO₃²⁻ ions.
∴ The no. of moles of NH₄⁺ ions in 0.05 mol of (NH₄)₂CO₃ = (2.0)(0.05 mol) = 0.1 mol.
3) Number of moles of carbonate ions :
Ammonium carbonate is dissociated according to the balanced equation:(NH₄)₂CO₃ → 2NH₄⁺ + CO₃²⁻.
It is clear that every 1.0 mole of (NH₄)₂CO₃ is dissociated to produce 2.0 moles of NH₄⁺ ions and 1.0 mole of CO₃²⁻ ions.
∴ The no. of moles of CO₃²⁻ ions in 0.05 mol of (NH₄)₂CO₃ = (1.0)(0.05 mol) = 0.05 mol.
4) Number of moles of hydrogen atoms:
Every 1.0 mol of (NH₄)₂CO₃ contains:2.0 moles of N atoms, 8.0 moles of H atoms, 1.0 mole of C atoms, and 3.0 moles of O atoms.
∴ The no. of moles of H atoms in 0.05 mol of (NH₄)₂CO₃ = (8.0)(0.05 mol) = 0.4 mol.
5) Number of hydrogen atoms:
It is known that every mole of a molecule or element contains Avogadro's number (6.022 x 10²³) of molecules or atoms.Using cross multiplication:
1.0 mole of H atoms contains → 6.022 x 10²³ atoms.
0.4 mole of H atoms contains → ??? atoms.
∴ The no. of atoms in 0.4 mol of H atoms = (6.022 x 10²³ molecules)(0.4 mole)/(1.0 mole) = 2.4 x 10²³ molecules.
Ответ:
thanks
Explanation: