Given 8.10g of butanoic acid and excess ethanol, how many grams of ethyl butyrate would be synthesized, assuming a complete 100% yield?
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Ответ:
10.7 g of ethyl butyrate would be synthesized in 100 % conversion
Explanation:
1 mol of butanoic acid produces 1 mol of ethyl butyrate in 100% conversion.
Number of moles = (mass/molar mass)
Molar mass of butanoic acid = 88.11 g/mol
Molar mass of ethyl butyrate = 116.16 g/mol
So, 8.10 g of butanoic acid =
butanoic acid = 0.09193 moles of butanoic acid
So, in 100 % conversion, moles of ethyl butyrate would be produced = 0.09193 moles
So, in 100 % conversion, mass of ethyl butyrate would be produced =
= 10.7 g
Ответ:
Further Explanation:
Stoichiometry:
It is used to determine the amount of species present in the reaction by the relationship between reactants and products. It is used to determine the moles of a chemical species when moles of other chemical species present in the reaction is given.
Consider the general reaction,
Here,
A is the reactant.
B is the reactant.
C is the product.
One mole of A reacts with two moles of B to produce three moles of C. The stoichiometric ratio between A and B is 1:2, the stoichiometric ratio between A and C is 1:3 and the stoichiometric ratio between B and C is 2:3.
The given reaction occurs as follows:
The formula to calculate the moles of
is as follows:
Substitute 8.10 g for the given mass of
and 88.11 g/mol for the molar mass of
in equation (1).
According to the stoichiometry of the reaction, one mole of
reacts with one mole of
to form one mole of
and one mole of
. So the number of moles of
produced by 0.0919 moles of are also 0.0919 mol.
The formula to calculate the mass of
is as follows:
Substitute 0.0919 mol for the moles of
and 116.16 g/mol for the molar mass of
in equation (2).
Since the yield is 100 %, so the amount of ethyl butyrate produced is 10.675 g.
Learn more:
1. Calculate the moles of chlorine in 8 moles of carbon tetrachloride:
2. Calculate the moles of ions in the solution:
Answer details:
Grade: Senior School
Subject: Chemistry
Chapter: Mole concept
Keywords: stoichiometry, ethyl butyrate, 0.0919 mol, one mole, 116.16 g/mol, 88.11 g/mol, 10.675 g.
Ответ:
2.998*10^8m/s 1hr K H D B D C M
=4996666.67 m/hr = 4996.67km/hr
1 60sec.