Given a 5.81g sample of h2 (fm =2.02), contained in a volume of 3.90l. how many atm of pressure would it have if the temperature was 64 degrees celsius?

The answer to your question is: P = 20.4 atm

Explanation:

Data

mass = 5.81 g

FM = 2.02

vol = 3.9 L

P = ?

T = 64°C = 337°K

R = 0.082 atm L / mol°K

Formula

               P = nRT / V

Process

              2.02 g  1 mol

              5.81 g  x

               x = (5.81 x 1) / 2.02

               x = 2.88 mol

             P = (2.88)(0.082)(337) / 3.9

             P = 20.4 atm

3

Explanation: