Given the following equation: 2 KClO₃ ➞ 2 KCl + 3 O₂, how many grams of O₂ can be produced by letting 5.00 moles of KClO₃ react? *
4 points
12.0 g of O₂
480 g of O₂
24.00 g of O₂
240 g of O₂
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Ответ:
240 g of O2
Explanation:
Ответ:
-30 (2w + 3) is the only one I can figure out.
I hope this helped tho!! :]